汇编实验5

1.

代码：

assume cs:code, ds:data, ss:stack
data segment
  dw 0123h, 0456h, 0789h, 0abch, 0defh, 0fedh, 0cbah, 0987h
data ends

stack segment
  dw 0, 0, 0, 0, 0, 0, 0, 0
stack ends

code segment
start:  mov ax,stack
        mov ss, ax
        mov sp,16
        
        mov ax, data
        mov ds, ax
        
        push ds:[0]
        push ds:[2]
        pop ds:[2]
        pop ds:[0]
        
        mov ax,4c00h
        int 21h

code ends
end start

data段中的数据为：

程序返回前，cs=076C，ss=076B，ds=076A

程序加载后，code段段地址为x，则data段的段地址为   x-2    ，stack段的段地址为    x-1 

2

.assume cs:code, ds:data, ss:stack
data segment
  dw 0123h, 0456h
data ends

stack segment
  dw 0, 0
stack ends

code segment
start:  mov ax,stack
        mov ss, ax
        mov sp,16
        
        mov ax, data
        mov ds, ax
        
        push ds:[0]
        push ds:[2]
        pop ds:[2]
        pop ds:[0]
        
        mov ax,4c00h
        int 21h

code ends
end start

data段中的数据为：

cs=076C   ss=076B   ds=076A

data段的段地址为x-2   stack段的段地址为x-1

3

assume cs:code, ds:data, ss:stack

code segment
start:  mov ax,stack
        mov ss, ax
        mov sp,16
        
        mov ax, data
        mov ds, ax
        
        push ds:[0]
        push ds:[2]
        pop ds:[2]
        pop ds:[0]
        
        mov ax,4c00h
        int 21h

code ends
data segment
  dw 0123h, 0456h
data ends

stack segment
  dw 0,0
stack ends
end start

data段的数据：

 

cs=076A   ss=076E   ds=076D

code段地址为x  data段的段地址为x+3   stack段的段地址为x+4

 

4.

1和2不能正确执行 。（3）的data和stack都在code之后，它的ip为0，所以可以正确执行。

5

assume cs:code
a segment
  db 1,2,3,4,5,6,7,8
a ends

b segment
  db 1,2,3,4,5,6,7,8
b ends

c segment   ;
  db 8 dup(0)
c ends        ;
code segment
start:
       ;?
code ends
end start


5.

assume cs:code
a1 segment
  db 1,2,3,4,5,6,7,8
a1 ends
b1 segment
  db 1,2,3,4,5,6,7,8
b1 ends
c1 segment  
  db 0,0,0,0,0,0,0,0       
c1 ends
code segment
start:
    mov bx,0
    mov dx,0
    mov cx,8
s:  mov dx,0
    mov ax,a1
    mov ds,ax
    add d1,[bx]
    mov ax,c1
    mov ds,ax
    mov [bx],dl
    inc bx
loop s
mov ax,4c00h
int 21h       
code ends
end start

 

6.assume cs:code
a segment
  dw 1,2,3,4,5,6,7,8,9,0ah,0bh,0ch,0dh,0eh,0fh,0ffh
a ends

b segment
  dw 8 dup(0)
b ends

code segment
start:
    mov ax,b
    mov ss,ax
    mov sp,10h
    
    mov ax,a
    mov ds,ax

    mov bx,0
    mov cx,8
    
    s: push [bx]
      add bx,2
    loop s

    mov ax,4c00h
    int 21h

    
code ends
end start
 

逆序存储成功

 

不知道自己第三个data段数据所求内容对不对

通过多次尝试了解了三个寄存器cs，ss，ds这三个段的段地址之间的关系

知道了程序入口的使用

 

 

转载于:https://www.cnblogs.com/zcrdbk/p/10012917.html