UDP示例

android学习笔记18--------------UDP示例

分类： android2011-11-10 10:07 848人阅读 评论(0) 收藏 举报

android buffer exception byte string import

参考别人一幅原理图。

 

 

[java]  view plain copy print ?

 

1. import java.io.IOException;  
2. import java.net.DatagramPacket;  
3. import java.net.DatagramSocket;  
4. import java.net.InetAddress;  
5.   
6. public class UDPClient  
7. {  
8.     private DatagramSocket client=null;  
9.     private DatagramPacket packet=null;  
10.     private InetAddress host=null;  
11.     public static int portSend=8888;  
12.     public static String name="192.168.142.199";  
13.       
14.       
15.     public UDPClient()  
16.     {         
17.         try  
18.         {  
19.             host = InetAddress.getByName(name);  
20.             client=new DatagramSocket();  
21.                                           
22.             System.out.println("客户端准备就绪");  
23.         } catch (Exception e)  
24.         {  
25.             e.printStackTrace();  
26.         }                             
27.     }  
28.       
29.     public void UDPClientRun(byte[] buffer) throws IOException    
30.     {                                 
31.         host = InetAddress.getByName(name);  
32.         packet=new DatagramPacket(buffer,buffer.length, host, portSend);  
33.         client.send(packet);      
34.         System.out.println("客户端发送消息");  
35.     }  
36.       
37.     public void UDPClientStop()  
38.     {  
39.         client.close();  
40.     }  
41. }  

 

[java]  view plain copy print ?

 

1. import java.io.IOException;  
2. import java.net.DatagramPacket;  
3. import java.net.DatagramSocket;  
4.   
5. public class UDPService  
6. {  
7.     private DatagramSocket server =null;  
8.     private DatagramPacket dPacket=null;  
9.     private byte[] buffer = new byte[640];    
10.     public static int portServer=8888;  
11.       
12.     public UDPService ()  
13.     {  
14.         try  
15.         {  
16.             server  = new DatagramSocket(portServer);     
17.             dPacket = new DatagramPacket(buffer, buffer.length);  
18.         } catch (Exception e)  
19.         {  
20.             e.printStackTrace();  
21.         }             
22.     }  
23.       
24.     public byte[] UDPServiceRun()  
25.     {                                                                                             
26.         try  
27.         {  
28.             server.receive(dPacket);  
29.             System.out.println("服务端接收到消息");  
30.         } catch (IOException e)  
31.         {  
32.             e.printStackTrace();  
33.             System.out.println("服务端未收到消息");  
34.         }                             
35.         return buffer;                        
36.     }  
37.       
38.     public void UDPSeverStop()  
39.     {  
40.         server.close();  
41.     }  
42.       
43.     public String getClientName()  
44.     {  
45.         String name="";  
46.         name=dPacket.getAddress().toString();  
47.         return name;  
48.     }  
49.       
50. }  

转载于:https://www.cnblogs.com/gtgl/p/4917834.html