相关算法如下: 有兴趣可以测试一下,希望能给你带来帮助 using System; using System.Text; using System.IO; namespace ts{ class test{ private static string[] startChars = {"啊", "芭", "擦","搭","蛾","发","噶","哈","击","击","喀","垃","妈","拿","哦","啪", "期","然", "撒","塌","挖","挖","挖","昔","压","匝"}; private static string[] endChars = {"澳", "怖", "错","堕","贰","咐","过","祸","啊","骏","阔","络","穆","诺","沤","瀑", "群","弱", "所","唾","啊","啊","误","迅","孕","座"}; /**//// <summary> /// 根据字符和对应的中文字符,转成SQL查询条件 /// </summary> /// <param name="cChar">要转化的字符,[A-Z]</param> /// <param name="strFieldName">条件左值</param> /// <returns>SQL条件</returns> /// <remarks> Sxf 2001-1-4 ***** JY 2002-1-4 </remarks> public static string GetCharCondition(char cChar, string strFieldName) { string strWord; int Index = (int)(char.ToUpper(cChar)) - (int)'A'; if (Index >= 0 && Index < 26) strWord = startChars[Index]; else strWord = startChars[0]; // return string.Format("(({0}>='{1}' AND {0}<'[') OR ({0} >= '{3}' AND {0} < '{{') OR {0}>='{2}')", // strFieldName, char.ToUpper(cChar), strWord, char.ToLower(cChar)); return string.Format("(({0} >= '{3}' AND {0} <= 'zzzzzzzz') OR {0}>='{2}')", strFieldName, char.ToUpper(cChar), strWord, char.ToLower(cChar)); } /**//// <summary> /// 将指定字段值的每个字符分割,这样可以生成同音查询的SQL /// </summary> /// <param name="fieldName">字段名</param> /// <param name="fieldValue">字段值</param> /// <returns>生成的可以进行同音查询的SQL</returns> public static string GetCharFullCondition(string fieldName, string fieldValue) { StringBuilder sql = new StringBuilder(1024); int i = 1; foreach (char c in fieldValue) { if (i > 1) sql.Append(" AND "); int index = (int)(char.ToUpper(c)) - (int)'A'; string startWord, endWord; if (index >= 0 && index < 26) { startWord = startChars[index]; endWord = endChars[index]; } else { startWord = startChars[0]; endWord = endChars[0]; } string subStr = String.Format("SUBSTRING({0}, {1}, {2})", fieldName, i, 1); sql.AppendFormat("({0} BETWEEN '{1}' AND '{2}')", subStr, startWord, endWord); ++i; } return sql.ToString(); } } }