php石头剪刀布五局三胜,求程序,下面是剪刀石头布的程序,谁能帮忙改成能选择三局两胜,五局三胜……的?能成功运行的加分...

// 只需要修改main() //#define AllCount 5 // 输入你要选择的赛制，5为五局三胜，3为三局两胜 //#define WinCount AllCount / 2 + 1 void main() { Play play; int a=5; int failure=0,win=0,tie=0; unsigned long begin; int WinCount; int AllCount; printf("输入你要选择的赛制：(请输入大于1的奇数)"); while(1) { scanf("%d", &AllCount); if(AllCount < 3 || AllCount % 2 == 0) { printf("输入错误，请重新输入!n"); printf("输入你要选择的赛制：(请输入大于1的奇数)"); } else { break; } } WinCount = AllCount / 2 + 1; while(a!=-1) { begin=GetTickCount(); cout<>a; system("cls"); if(a<=2 && a>-1) { play.Set_People(a); play.Set_Computer(begin%3); switch(play.Judge()) { case 1: //cout<