转换时间为 “XX分钟之前”-优快云博客

本文介绍了一个计算字符串形式日期与当前时间的时间差，并将其转换为易于理解的表达方式的方法。通过一系列条件判断，该方法能够返回诸如“当前”、“秒之前”、“分钟之前”等描述，便于用户快速了解时间跨度。

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public static string getTimeAgo(string strDate)
    {
        string strTime = string.Empty;
        if (clsCommon.IsDate(strDate))
        {
            TimeSpan t = DateTime.UtcNow - Convert.ToDateTime(strDate);
            double deltaSeconds = t.TotalSeconds;

            double deltaMinutes = deltaSeconds / 60.0f;
            int minutes;

            if (deltaSeconds < 5)
            {
                return "当前";
            }
            else if (deltaSeconds < 60)
            {
                return Math.Floor(deltaSeconds) + " 秒之前";
            }
            else if (deltaSeconds < 120)
            {
                return "分钟之前";
            }
            else if (deltaMinutes < 60)
            {
                return Math.Floor(deltaMinutes) + " minutes ago";
            }
            else if (deltaMinutes < 120)
            {
                return "An hour ago";
            }
            else if (deltaMinutes < (24 * 60))
            {
                minutes = (int)Math.Floor(deltaMinutes / 60);
                return minutes + " hours ago";
            }
            else if (deltaMinutes < (24 * 60 * 2))
            {
                return "Yesterday";
            }
            else if (deltaMinutes < (24 * 60 * 7))
            {
                minutes = (int)Math.Floor(deltaMinutes / (60 * 24));
                return minutes + " days ago";
            }
            else if (deltaMinutes < (24 * 60 * 14))
            {
                return "Last week";
            }
            else if (deltaMinutes < (24 * 60 * 31))
            {
                minutes = (int)Math.Floor(deltaMinutes / (60 * 24 * 7));
                return minutes + " weeks ago";
            }
            else if (deltaMinutes < (24 * 60 * 61))
            {
                return "Last month";
            }
            else if (deltaMinutes < (24 * 60 * 365.25))
            {
                minutes = (int)Math.Floor(deltaMinutes / (60 * 24 * 30));
                return minutes + " months ago";
            }
            else if (deltaMinutes < (24 * 60 * 731))
            {
                return "Last year";
            }

            minutes = (int)Math.Floor(deltaMinutes / (60 * 24 * 365));
            return minutes + " years ago";
        }
        else
        {
            return "";
        }
    }

调用方法：
getTimeAgo(DateTime.Now.ToString());