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最新推荐文章于 2019-07-17 17:57:00 发布

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最新推荐文章于 2019-07-17 17:57:00 发布

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原文链接：http://www.cnblogs.com/jassin-du/p/7696356.html

本文提供了多个Python编程示例，包括使用while循环进行特定数字序列的打印、求1到100的和、输出指定范围内的奇数、以及计算交错正负数之和等问题的解决方法。

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#1、使用while循环输入 1 2 3 4 5 6 8 9 10
#方法一：
# count = 1
# flag = True
# while flag:
#     if count == 7:
#         print('')
#         count += 1
#     print(count)
#     count = count + 1  # count += 1
#     if count == 11:
#         flag = False

#方法二：
# count = 1
# flag = True
# while flag:
#     # print(count)
#     if count == 7:
#         print('')
#     else:print(count)
#     count = count + 1  # count += 1
#     if count == 11:
#         flag = False

#方法三：
# count = 1
# while count < 11:
#     if count == 7:
#         print('')
#     else:print(count)
#     count = count + 1  # count += 1

count = 1
while count < 10:
    count += 1
    if count == 7
        continue
    else:
        print(count)



#2、求1-100的所有数的和

# count = 1
# sum = 0
# while count < 101:
#     # sum2 = count
#     sum =  sum + count  # sum += count
#     count = count + 1
# print(sum)

#3、输出 1-100 内的所有奇数
#1,3,5,7,9.。。。。。
#方法一：
# count = 1
# while count < 101:
#     print(count)
#     count += 2
#方法二：
# count = 1
# while count < 101:
#     if count % 2 == 1:
#         print(count)
#     count += 1

# 5、求1-2+3-4+5 ... 99的所有数的和

n = 1
sum = 0
while n < 100:
if n % 2 == 0:
        n = -n
    sum = sum + n
if n % 2 == 0:
        n = -n
    n += 1
print('1-2+3-4+5 ... 99的所有数的和为%d'%sum)#相当于print(sum)

# sum = 1
# add = 0
# while sum < 100:
#     if sum % 2 == 1:
#         add = add + sum
#     else:
#         add = add - sum
#     sum += 1
# print(add)