LeetCode-3Sum Closest

最新推荐文章于 2024-04-29 23:48:08 发布

转载最新推荐文章于 2024-04-29 23:48:08 发布 · 54 阅读

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原文链接：http://www.cnblogs.com/incrediblechangshuo/p/5693746.html

本文介绍了一种寻找数组中三个整数之和最接近给定目标值的方法，并提供了一个具体的实现方案。通过排序和双指针技巧，有效地解决了这个问题。

Given an array S of n integers, find three integers in S such that the sum is closest to a given number, target. Return the sum of the three integers. You may assume that each input would have exactly one solution.

    For example, given array S = {-1 2 1 -4}, and target = 1.

    The sum that is closest to the target is 2. (-1 + 2 + 1 = 2).

public class Solution {
    
    public int threeSumClosest(int[] nums, int target) {
        int diff=Integer.MAX_VALUE;
        int res=0;
        if(nums==null && nums.length==0){
            return 0;
        }
        Arrays.sort(nums);
        int len=nums.length;
        for(int i=0; i<len-2; i++){
            if(!(i>0 && nums[i]==nums[i-1])){
                int sum=getSum(nums, i, target);
                if(Math.abs(target-sum)<diff){
                    diff=Math.abs(target-sum);
                    res=sum;
                }
            }
        }
        return res;
    }
    public int getSum(int[] nums, int index, int target){
        
        int first=nums[index];
        int left=index+1;
        int right=nums.length-1;
        int diff=Integer.MAX_VALUE;
        int res=0;
        while(left<right){
            boolean valid=true;
            if(left>index+1 && nums[left]==nums[left-1]){
                left++;
                valid=false;
            }
            if(right<nums.length-1 && nums[right]==nums[right+1]){
                right--;
                valid=false;
            }
            if(valid){
                int sum=first+nums[left]+nums[right];
                if(Math.abs(target-sum)<diff){
                    diff=Math.abs(target-sum);
                    res=sum;
                }
                if((target-sum)>=0){
                    left++;
                }
                else{
                    right--;
                }
            }
        }
        return res;
    }
}

转载于:https://www.cnblogs.com/incrediblechangshuo/p/5693746.html