#!/usr/bin/env python
# -*- coding:utf-8 -*-
l = [1, 8, 3, 5, 6, 2, 4, 7, 9, 0]
for end in range(len(l))[::-1]:
flag = False # 标志判断是否有交换
for i in range(0,end):
if l[i] > l[i+1]:
temp = l[i]
l[i] = l[i+1]
l[i+1] = temp
flag = True
if flag == False: # 如果遍历一次没有发生交换,说明该序列已经有序,结束排序
break
print l
转载于:https://blog.51cto.com/zgw285763054/1892966