python文件锁

最新推荐文章于 2025-05-19 14:48:45 发布

weixin_33719619

最新推荐文章于 2025-05-19 14:48:45 发布

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CC 4.0 BY-SA版权

文章标签： python

原文链接：https://my.oschina.net/1123581321/blog/833480

2019独角兽企业重金招聘Python工程师标准>>>

不跨机器

import os
import time
import errno


class FileLockException(Exception):
    pass


class FileLock(object):
    def __init__(self, file_name, timeout=10, delay=.05):
        self.is_locked = False
        self.lockfile = os.path.join(os.getcwd(), '%s.lock' % file_name)
        self.file_name = file_name
        self.timeout = timeout
        self.delay = delay

    def acquire(self):
        start_time = time.time()
        while True:
            try:
                self.fd = os.open(self.lockfile, os.O_CREAT | os.O_EXCL | os.O_RDWR)
                break
            except OSError as e:
                if e.errno != errno.EEXIST:
                    raise
                if (time.time() - start_time) >= self.timeout:
                    raise FileLockException('Timeout')
                time.sleep(self.delay)
        self.is_locked = True

    def release(self):
        if self.is_locked:
            os.close(self.fd)
            os.unlink(self.lockfile)
            self.is_locked = False

    def __enter__(self):
        if not self.is_locked:
            self.acquire()
        return self

    def __exit__(self, type, value, traceback):
        if self.is_locked:
            self.release()

    def __del__(self):
        self.release()

转载于:https://my.oschina.net/1123581321/blog/833480