python怎么返回true,python没有返回true

I have a function, generally described as so:

def function(args):

if condition:

if condition2:

function(args+1)

elif condition3:

print "text"

return True

else:

return False

which is used in:

if function(args):

print "ok"

so here basically "text" will print out when condition3 is true but it

will not print out "ok" when condition3 is true. When it''s true it

should print out borth "text" and "ok"

解决方案"agent-s"

I have a function, generally described as so:

def function(args):

if condition:

if condition2:

function(args+1)

elif condition3:

print "text"

return True

else:

return False

You''ve simplified this, presumably to make the code more

clear. Unfortunately what remains isn''t executable, so we can''t see

the behaviour that confuses you.

Please write a minimal example that demonstrates the behaviour you

want explained.

--

\ "I doubt, therefore I might be." -- Anonymous |

`\ |

_o__) |

Ben Finney

On Feb 14, 4:15 pm, "agent-s"

I have a function, generally described as so: def function(args):

if condition:

if condition2:

function(args+1)

return None

elif condition3:

print "text"

return True

else:

return False

else:

return None

There are two cases, indicated above, where you don''t explicitly do a

"return", so you fall off the end of the function, and Python returns

None.

Then when the function''s caller tests the returned value, None is

treated as logically false.

which is used in:

if function(args):

print "ok"

so here basically "text" will print out when condition3 is true but it

will not print out "ok" when condition3 is true. When it''s true it

should print out borth "text" and "ok"

In the second last sentence, it is difficult to determine what you

think is expected behaviour and what you say is the actual behaviour.

In the last sentence, what does the first "it" refer to?

If the knowledge about returning None doesn''t help you, try some

standard(??) techniques like inserting print statements or debugger

break-points.

HTH,

John

On Tue, 13 Feb 2007 21:15:19 -0800, agent-s wrote:

I have a function, generally described as so:

[snip function]

which is used in:

if function(args):

print "ok"

so here basically "text" will print out when condition3 is true but it

will not print out "ok" when condition3 is true. When it''s true it

should print out borth "text" and "ok"

Thank you for sharing. Do you have an actual question?

--

Steven D''Aprano