java leftshift,Java BigInteger shiftLeft()用法及代码示例

java.math.BigInteger.shiftLeft(int n)方法返回一个BigInteger，其值为(this

用法:

public BigInteger shiftLeft(int n)

参数：该方法采用整数类型的一个参数n，它表示移位距离(以位为单位)。

返回值：该方法将位左移n次后返回BigInteger。

异常：如果移位距离为Integer.MIN_VALUE，则该方法可能会引发ArithmeticException。

例子：

Input: value = 2300, shift distance = 3

Output: 18400

Explanation:

Binary Representation of 2300 = 100011111100

shift distance = 3

after shifting 100011111100 left 3 times then

Binary Representation becomes 100011111100000

and Decimal equivalent of 100011111100000 is 18400.

Another way of expressing the same can be 2300*(2^3)=18400

Input: value = 35000, index = 5

Output: 1120000

以下示例程序旨在说明BigInteger的shiftLeft(index)方法。

// Program to demonstrate shiftLeft() method of BigInteger

import java.math.*;

public class GFG {

public static void main(String[] args)

{

// Creating BigInteger object

BigInteger biginteger = new BigInteger("2300");

// Creating a int i for Shift Distance

int i = 3;

// Call shiftLeft() method on bigInteger at index i

// store the return value as BigInteger

BigInteger changedvalue = biginteger.shiftLeft(i);

String result = "After applying ShiftLeft by Shift Distance " + i

+ " on " + biginteger + " New Value is " + changedvalue;

// Printing result

System.out.println(result);

}

}

输出：

After applying ShiftLeft by Shift Distance 3 on 2300 New Value is 18400