求400以内的亲密对数c语言,有谁会做C++的程序设计？帮忙做一下这个程序：求400以内的亲密对数...

#include#define N 400

struct intimate{

int n;

int sum;

int flag;

};

int FactorSum(int fac) // 亲密对数计算

{

int sum = 1;

int temp = 0;

int ret = sqrtf(fac);

if(fac == 1)

{

return sum = 1;

}

for(int i = 2; i <= ret; i++)

{

if(0 == fac%i)

{

temp = fac/i;

sum = sum + temp + i;

}

}

if(ret == sqrtf(fac))

{

sum = sum - ret;

}

return sum;

}

int IntimatePair(int range) //查找亲密对数输出

{

int count = 0;

struct intimate inti[N];

for(int i = 0; i < N; i++)

{

inti[i].n = i + 1;

inti[i].sum = FactorSum(i + 1);

inti[i].flag = 0;

}

for(int i = 0; i < N; i++)

printf("inti[%d] = %d\n", i + 1,inti[i].sum);

for(int j = 0; j < N; j++)

{

if(inti[j].flag == 0)

{

for(int k = j + 1; k < N; k++)

{

if(inti[j].sum == inti[k].n && inti[j].n == inti[k].sum && inti[k].flag == 0)

{

inti[j].flag = 1;

inti[k].flag = 2;

printf("%d ,%d\n",inti[j].n,inti[k].n);

}

}

}

}

return count;

}

int main()

{

IntimatePair(N);

return 0;

}