PAT 1020 Tree Traversals

最新推荐文章于 2024-05-13 09:10:43 发布

转载最新推荐文章于 2024-05-13 09:10:43 发布 · 55 阅读

0 ·

CC 4.0 BY-SA版权

原文链接：http://www.cnblogs.com/cunyusup/p/10801579.html

博客围绕二叉树展开，已知二叉树所有键为不同正整数，给出后序和中序遍历序列，要求输出对应二叉树的层序遍历序列。还说明了输入、输出的规格，以及给出了示例输入和输出。

摘要生成于 C知道，由 DeepSeek-R1 满血版支持，前往体验 >

1020 Tree Traversals (25 分)

Suppose that all the keys in a binary tree are distinct positive integers. Given the postorder and inorder traversal sequences, you are supposed to output the level order traversal sequence of the corresponding binary tree.

Input Specification:

Each input file contains one test case. For each case, the first line gives a positive integer

Output Specification:

For each test case, print in one line the level order traversal sequence of the corresponding binary tree. All the numbers in a line must be separated by exactly one space, and there must be no extra space at the end of the line.

Sample Input:

7
2 3 1 5 7 6 4
1 2 3 4 5 6 7

Sample Output:

4 1 6 3 5 7 2

#include<bits/stdc++.h>
using namespace std;
typedef long long ll;

struct node{
    int data = -1;
    node *left = NULL;
    node *right = NULL;
};
int n,cnt;

int a[31];
int b[31];

node* createtree(int start,int end){
    if(start > end)
        return NULL;
    int num = a[cnt--];
    node *t = new(node);
    t->data = num;
    if(start == end){ return t;}

    int pos = -1;
    for(int i=start;i <= end;i++){
        if(b[i] == num) pos = i;
    }

    t->right = createtree(pos+1,end);
    t->left = createtree(start,pos-1);

    return t;
}



int main(){
    cin >> n;
    cnt = n-1;

    for(int i=0;i < n;i++) cin >> a[i];
    for(int i=0;i < n;i++) cin >> b[i];

    node *root = createtree(0,n-1);

    queue<node*> que;
    que.push(root);
    int count = 0;

    while(!que.empty()){
        node *t = que.front();que.pop();
        cout << t->data;
        if(count!=n-1){cout << " ";count++;}
        if(t->left)que.push(t->left);
        if(t->right)que.push(t->right);
    }



    return 0;
}

创建节点要new，不然就会出错

转载于:https://www.cnblogs.com/cunyusup/p/10801579.html