HDU 1241(Oil Deposits)

题目链接地址:http://acm.hdu.edu.cn/showproblem.php?pid=1241

/*简单DFS
题意：就相当于求连通分量的个数
*/

#include<iostream>
#include<algorithm>
using namespace std;
#define maxn 101
char matrix[maxn][maxn];
bool visited[maxn][maxn];
int dir[][2] = {{0,-1},{1,0},{0,1},{-1,0},{-1,-1},{-1,1},{1,-1},{1,1}};
int m,n;
bool ok(int i,int j)
{
    return i >= 1 && i <= m && j >= 1 && j <= n && matrix[i][j] == '@';
}
void dfs(int x,int y)
{
    int p,q;
    for(int i = 0; i < 8; i++)
    {
        p = x + dir[i][0],q = y + dir[i][1];
        if(ok(p,q) && !visited[p][q])
            visited[p][q] = true,dfs(p,q);
    }
}
void solve()
{
    int ans,num_size;
    num_size = 0,ans = 0;
    memset(visited,false,sizeof(visited));
    for(int i = 1; i <= m; i++)
        for(int j = 1; j <= n; j++)
        {
            if(!visited[i][j] && matrix[i][j] == '@')
                ans++,visited[i][j] = true,dfs(i,j);
        }
    printf("%d\n",ans);    
}
int main()
{
    //freopen("1002.txt","r",stdin);
    while(scanf("%d%d",&m,&n) && (m||n))
    {
        int i,j;
        for(i = 1; i <= m; i++)
            for(j = 1; j <= n; j++)
                cin >> matrix[i][j];
        solve();
    }
    return 0;
}

 

转载于:https://www.cnblogs.com/sorryhao/archive/2012/10/11/2720352.html