分组求行数
SELECT DateTime,AgentName ,Count(SessionId)as DayWorkSum ,1 as DayWork FROM cti_record WHERE Date ='2012-03-04' and AgentName in (1006,1013 )
group by AgentName
将结果集插入另一个表中
insert into rep_agentworksum (DateTime,AgentName ,DayWorkSum , DayWork )
SELECT DateTime,AgentName ,Count(SessionId)as DayWorkSum ,1 as DayWork FROM cti_record WHERE Date ='2012-03-04' and AgentName in (1006,1013 )
group by AgentName