LeetCode 412. Fizz Buzz

最新推荐文章于 2022-07-27 11:33:06 发布

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最新推荐文章于 2022-07-27 11:33:06 发布

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原文链接：http://www.cnblogs.com/A-Little-Nut/p/10066877.html

本文介绍了一个经典的编程问题——FizzBuzz问题，并提供了一种使用C++编程语言的解决方案。该程序能输出从1到指定数字n的字符串表示，其中3的倍数输出为'Fizz'，5的倍数输出为'Buzz'，同时是3和5的倍数则输出'FizzBuzz'。

Write a program that outputs the string representation of numbers from 1 to n.

But for multiples of three it should output “Fizz” instead of the number and for the multiples of five output “Buzz”. For numbers which are multiples of both three and five output “FizzBuzz”.

Example:

n = 15,

Return:
[
    "1",
    "2",
    "Fizz",
    "4",
    "Buzz",
    "Fizz",
    "7",
    "8",
    "Fizz",
    "Buzz",
    "11",
    "Fizz",
    "13",
    "14",
    "FizzBuzz"
]

分析
Easy

class Solution {
public:
    vector<string> fizzBuzz(int n) {
          vector<string> res;
          for(int i=1;i<=n;i++){
              if(i%3==0&&i%5==0)
                 res.push_back("FizzBuzz");
              else if(i%3==0)
                 res.push_back("Fizz");
              else if(i%5==0)
                 res.push_back("Buzz");
              else{
                  string s=to_string(i);
                  res.push_back(s);
              }
          }
        return res;
    }
};

转载于:https://www.cnblogs.com/A-Little-Nut/p/10066877.html