Leetcode 197. Rising Temperature (Database)

最新推荐文章于 2025-09-11 20:53:34 发布

weixin_30915275

最新推荐文章于 2025-09-11 20:53:34 发布

阅读量117

点赞数

CC 4.0 BY-SA版权

文章标签：数据库

原文链接：http://www.cnblogs.com/lettuan/p/6289213.html

本文介绍了一种使用SQL查询的方法，旨在找出比前一天温度高的所有日期的ID。通过使用TO_DAYS函数来比较连续两天的日期，并结合子查询，能够有效地筛选出符合条件的数据。

Given a Weather table, write a SQL query to find all dates' Ids with higher temperature compared to its previous (yesterday's) dates.

+---------+------------+------------------+
| Id(INT) | Date(DATE) | Temperature(INT) |
+---------+------------+------------------+
|       1 | 2015-01-01 |               10 |
|       2 | 2015-01-02 |               25 |
|       3 | 2015-01-03 |               20 |
|       4 | 2015-01-04 |               30 |
+---------+------------+------------------+

For example, return the following Ids for the above Weather table:

+----+
| Id |
+----+
|  2 |
|  4 |
+----+

思路：

TO_DAYS(date)可以将日期转换成公元后的天数。

# Write your MySQL query statement below
select w1.Id from Weather as w1, Weather as w2
WHERE TO_DAYS(w1.Date) = TO_DAYS(w2.Date) + 1 and w1.Temperature > w2.Temperature