统计每个季度的数据

最新推荐文章于 2020-05-22 17:55:57 发布

转载最新推荐文章于 2020-05-22 17:55:57 发布 · 341 阅读

0 ·

CC 4.0 BY-SA版权

原文链接：http://www.cnblogs.com/shiruina/p/9355096.html

文章标签：

#java

本文介绍了一种方法，用于根据指定年份和季度获取透析统计数据。通过使用C#编程语言实现，该方法能够从基础统计数据中筛选并汇总每个季度不同透析方式的频率。

摘要生成于 C知道，由 DeepSeek-R1 满血版支持，前往体验 >

 private object GetSeasonDataByYear(DateTime thisTime,
            List<DailyDialysisWayStatistic> baseStatisticsList, List<string> dialysisWayList)
        {
            //源格式：透析方式-季度数组
            List<Tuple<string, object>> tupleList = new List<Tuple<string, object>>();

            var seasonGroups = new[] { "第一季度", "第二季度", "第三季度", "第四季度" };
            dialysisWayList.ForEach(y =>
            {
                int[] countGroups = new int[4];
                for (int i = 1; i <= seasonGroups.Length; i++)
                {
                    DateTime[] seasonDate = GetSeasonDate(thisTime.Year, i);
                    var count = baseStatisticsList
                        .Where(z => z.DialysisWay == y && z.DialysisDate >= seasonDate.First() &&
                                    z.DialysisDate <= seasonDate.Last())
                        .Sum(x => x.Frequency);
                    countGroups[i - 1] = count;
                }
                tupleList.Add(new Tuple<string, object>(y, countGroups));
            });

            return new { seasonGroups, tupleList };
        }



 /// <summary>
        /// 获取输入年-季度的第一天与最后一天
        /// </summary>
        /// <param name="thisYear">当前年</param>
        /// <param name="seasonNum">季度序号</param>
        /// <returns></returns>
        private DateTime[] GetSeasonDate(int thisYear, int seasonNum = 1)
        {
            var firstDate = new DateTime(thisYear, (seasonNum - 1) * 3 + 1, 1);

            //季度最后一天默认30号,1-4季度为31号.
            var day = seasonNum == 1 || seasonNum == 4 ? 31 : 30;
            var lastDate = new DateTime(thisYear, (seasonNum - 1) * 3 + 3, day);

            return new[] { firstDate, lastDate };
        }