HDOJ_acm steps_1.1.8

本文提供了一个程序示例,用于计算输入整数序列的总和,并在每次计算后输出结果,中间用换行符分隔。
Problem Description
Your task is to calculate the sum of some integers.
 
Input
Input contains an integer N in the first line, and then N lines follow. Each line starts with a integer M, and then M integers follow in the same line.
 
Output
For each group of input integers you should output their sum in one line, and you must note that there is a blank line between outputs.
 
Sample Input
3
4 1 2 3 4
5 1 2 3 4 5
3 1 2 3
 
Sample Output
10

15

6
 
Author
lcy
 
 
Recommend
JGShining
 

#include<stdio.h>
main()
{
      int n;
      while(scanf("%d",&n)!=EOF)
      {   while(n--)
          {   int m,sum=0;
              scanf("%d",&m);
              while(m--)
              {   int i;
                  scanf("%d",&i);
                   sum=sum+i;
                 }
              printf("%d\n",sum);
              if(n)
              printf("\n");
              }
          }
          return 0;
}
         
 

转载于:https://www.cnblogs.com/artemisia/archive/2012/03/25/2417099.html

评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值