POJ 2017 No Brainer(超级水题)

最新推荐文章于 2017-02-20 19:38:32 发布

转载最新推荐文章于 2017-02-20 19:38:32 发布 · 51 阅读

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原文链接：http://www.cnblogs.com/AndyDai/p/4734187.html

文章标签：

#java #数据结构与算法 #运维

本文介绍了一个关于僵尸吃脑的趣味编程问题及其解决方案。问题要求根据僵尸所吃的脑数量与生存所需的脑数量来判断其能否存活，并给出了具体的输入输出样例及Java实现代码。

一、Description

Zombies love to eat brains. Yum.

Input

The first line contains a single integer n indicating the number of data sets.

The following n lines each represent a data set. Each data set will be formatted according to the following description:

A single data set consists of a line "X Y", where X is the number of brains the zombie eats and Y is the number of brains the zombie requires to stay alive.

Output

For each data set, there will be exactly one line of output. This line will be "MMM BRAINS" if the number of brains the zombie eats is greater than or equal to the number of brains the zombie requires to stay alive. Otherwise, the line will be "NO BRAINS".
二、题解
只做为工作记录，不多说。
三、Java代码

import java.util.Scanner; 

public class Main {
	
    public static void main(String[] args) { 
       Scanner cin = new Scanner(System.in);
       int n,i,a,b;
       n=cin.nextInt();
       for(i=1;i<=n;i++){
    	   a=cin.nextInt();
    	   b=cin.nextInt();
    	   if(a>=b)
    		   System.out.println("MMM BRAINS");
    	   else
    		   System.out.println("NO BRAINS");
       }
    } 
  }

转载于:https://www.cnblogs.com/AndyDai/p/4734187.html