题目描述
有一个复杂链表,其结点除了有一个m_pNext指针指向下一个结点外,还有一个m_pSibling指向链表中的任一结点或者NULL,请完成函数ComplexListNode* Clone(ComplexListNode* pHead),以复制一个复杂链表。结点的定义如下:
struct ComplexListNode
{
int m_nValue;
ComplexListNode* m_pNext;
ComplexListNode* m_pSibling;
};
题目分析
剑指Offer(纪念版)P147
代码实现
ComplexListNode* Clone(ComplexListNode* pHead)
{
CloneNodes(pHead);
ConnectSiblingNodes(pHead);
return ReconnectNodes(pHead);
}
void CloneNodes(ComplexListNode* pHead)
{
ComplexListNode* pNode = pHead;
while(pNode != NULL)
{
ComplexListNode* pCloned = new ComplexListNode();
pCloned->m_nValue = pNode->m_nValue;
pCloned->m_pNext = pNode->m_pNext;
pCloned->m_pSibling = NULL;
pNode->m_pNext = pCloned;
pNode = pCloned->m_pNext;
}
}
void ConnectSiblingNodes(ComplexListNode* pHead)
{
ComplexListNode* pNode = pHead;
while(pNode != NULL)
{
ComplexListNode* pCloned = pNode->m_pNext;
if(pNode->m_pSibling != NULL)
{
pCloned->m_pSibling = pNode->m_pSibling->m_pNext;
}
pNode = pCloned->m_pNext;
}
}
ComplexListNode* ReconnectNodes(ComplexListNode* pHead)
{
ComplexListNode* pNode = pHead;
ComplexListNode* pClonedHead = NULL;
ComplexListNode* pClonedNode = NULL;
if(pNode != NULL)
{
pClonedHead = pClonedNode = pNode->m_pNext;
pNode->m_pNext = pClonedNode->m_pNext;
pNode = pNode->m_pNext;
}
while(pNode != NULL)
{
pClonedNode->m_pNext = pNode->m_pNext;
pClonedNode = pClonedNode->m_pNext;
pNode->m_pNext = pClonedNode->m_pNext;
pNode = pNode->m_pNext;
}
return pClonedHead;
}