Java 中的值传递和引用传递问题

Java值传递与引用传递详解
本文通过具体的Java代码示例,深入解析了值传递和引用传递的区别,展示了基本类型和对象类型在方法调用中如何被处理,以及这如何影响原始数据的状态。

Java 中的值传递和引用传递问题

public class Operation {
    int data = 50;

    void change(int data) {
        data = data + 100;
    }

    public static void main(String[] args) {
        Operation op = new Operation();
        System.out.println("before change: " + op.data);
        op.change(200);
        System.out.println("after change: " + op.data);
    }
}

点击查看结果

before change: 50
after change: 50
public class Operation2 {
    int data = 50;

    void change(Operation2 op) {
        op.data = op.data + 100;
    }

    public static void main(String args[]) {
        Operation2 op = new Operation2();
        System.out.println("before change " + op.data);
        op.change(op);
        System.out.println("after change " + op.data);
    }
}

点击查看结果

before change 50
after change 150

Dog 类

public class Dog {
    String name;

    Dog(String name) {
        this.name = name;
    }

    String getName() {
        return this.name;
    }

    void setName(String name) {
        this.name = name;
    }

    String getObjectAddress() {
        return super.toString();
    }
}
public class PassByValueExample {
    public static void main(String[] args) {
        Dog dog = new Dog("A");
        System.out.println(dog.getObjectAddress());
        System.out.println("------------------------");
        func(dog);
        System.out.println("------------------------");
        System.out.println(dog.getObjectAddress());
        System.out.println(dog.getName());
    }

    private static void func(Dog dog) {
        System.out.println(dog.getObjectAddress());
        dog = new Dog("B");
        System.out.println(dog.getObjectAddress());
        System.out.println(dog.getName());
    }
}

点击查看结果

Dog@1b6d3586
------------------------
Dog@1b6d3586
Dog@4554617c
B
------------------------
Dog@1b6d3586
A

Process finished with exit code 0
public class PassByValueExample2 {
    public static void main(String[] args) {
        Dog dog = new Dog("A");
        func(dog);
        System.out.println(dog.getName());
    }

    private static void func(Dog dog) {
        dog.setName("B");
    }
}

点击查看结果

B

转载于:https://www.cnblogs.com/hglibin/p/10093350.html

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