sql server 按年月日分组

最新推荐文章于 2022-12-08 08:18:44 发布

转载最新推荐文章于 2022-12-08 08:18:44 发布 · 619 阅读

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原文链接：http://www.cnblogs.com/yangjinwang/p/6648408.html

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#数据库

本文介绍了一种在 SQL Server 中根据不同的时间维度（年、月、日）进行数据分组的方法，通过存储过程实现对特定活动期间各种奖品发放数量的统计。

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sql server 按年月日分组

-----------------------------------------------
--author:yangjinwang
--date:2017-03-30
--do:根据活动查询 每个奖品类的发放数量
-----------------------------------------------
create proc GetWinningInfoTypeCountByTimeActivity
@CreateTimeStart datetime =null,  --开始时间
@CreateTimeEnd datetime =null,  --结束时间
@TimeType varchar(20)='m',   --查询维度，年月日
@ActivityId int=null         --活动ID
as
begin
    if(@TimeType='y')
        begin
            select  
            c.id as '活动ID',
            c.Name  as '活动名称',
            cast(datepart(YEAR,a.CreateTime) as varchar(4))   as  '日期',
            b.Title as  '奖品类别'
            ,COUNT(a.Id) as '中奖数量'
            from  WinningInfo  a 
            left join PrizesInfo b on a.PrizesId=b.Id
            left join ActivityInfo  c on b.ActivityId=c.Id
            where  a.ActivityId=@ActivityId
            and (a.CreateTime>=@CreateTimeStart or @CreateTimeStart is null)
            and (a.CreateTime<=@CreateTimeEnd or @CreateTimeEnd is null)
             group by c.id,c.Name  ,  
            cast(datepart(YEAR,a.CreateTime) as varchar(4)) ,
            b.Title
            order by 日期
        end
        else if(@TimeType='m')
            begin
                select  
                c.id as '活动ID',
                c.Name  as '活动名称',
                cast(datepart(YEAR,a.CreateTime) as varchar(4))+'-'+RIGHT('00'+CAST(MONTH(a.CreateTime) AS VARCHAR(2)),2)     as  '日期',
                b.Title as  '奖品类别'
                ,COUNT(a.Id) as '中奖数量'
                from  WinningInfo  a 
                left join PrizesInfo b on a.PrizesId=b.Id
                left join ActivityInfo  c on b.ActivityId=c.Id
                where  a.ActivityId=@ActivityId
                and (a.CreateTime>=@CreateTimeStart or @CreateTimeStart is null)
                and (a.CreateTime<=@CreateTimeEnd or @CreateTimeEnd is null)
                 group by c.id,c.Name  ,  
                cast(datepart(YEAR,a.CreateTime) as varchar(4))+'-'+RIGHT('00'+CAST(MONTH(a.CreateTime) AS VARCHAR(2)),2)  ,
                b.Title
                order by 日期    
            end
        else
            begin
                    select  
                c.id as '活动ID',
                c.Name  as '活动名称',
                cast(datepart(YEAR,a.CreateTime) as varchar(4))+'-'+RIGHT('00'+CAST(MONTH(a.CreateTime) AS VARCHAR(2)),2)+'-'+RIGHT('00'+CAST(day(a.CreateTime) AS VARCHAR(2)),2)     as  '日期',
                b.Title as  '奖品类别'
                ,COUNT(a.Id) as '中奖数量'
                from  WinningInfo  a 
                left join PrizesInfo b on a.PrizesId=b.Id
                left join ActivityInfo  c on b.ActivityId=c.Id
                where  a.ActivityId=@ActivityId
                and (a.CreateTime>=@CreateTimeStart or @CreateTimeStart is null)
                and (a.CreateTime<=@CreateTimeEnd or @CreateTimeEnd is null)
                 group by c.id,c.Name  ,  
                cast(datepart(YEAR,a.CreateTime) as varchar(4))+'-'+RIGHT('00'+CAST(MONTH(a.CreateTime) AS VARCHAR(2)),2)+'-'+RIGHT('00'+CAST(day(a.CreateTime) AS VARCHAR(2)),2)   ,
                b.Title
                order by 日期    
            end    
end

年，月，日，季，旬

--还可以这样
--年
select datepart(YEAR,getdate())
select datepart(yyyy,getdate())
select datepart(yy,getdate())
--月
select datepart(MONTH,getdate())
select datepart(mm,getdate())
select datepart(m,getdate())
--日
select datepart(dd,getdate())
--1年中的第多少天
select datepart(dy,getdate())
--季度
select datepart(qq,getdate())

select datepart(qq,'2017-07-01')
--1年中的第多少周
select datepart(wk,getdate())
--星期 --因为从周日算第一天的，星期4，计算结果是5
select datepart(dw,getdate())-1


SELECT CONVERT(VARCHAR(10),GETDATE(),120)  --2015-07-13
SELECT CONVERT(VARCHAR(10),GETDATE(),101)  --07/13/2015


--按日分组：
select convert(nvarchar(10),GETDATE(),120)
--按年月分组：
select  cast(datepart(YEAR,GETDATE()) as varchar(4))+'-'+RIGHT('00'+CAST(MONTH(GETDATE()) AS VARCHAR(2)),2) 
--按年分组
select DATEPART(year,GETDATE())


--按旬分组
 select case (datepart(day,GETDATE())-1)/10 when 0 then '上旬' when 1 then '中旬' else '下旬' end as 旬,
 sum(1) as 统计 
 from 表A group by 
 case (datepart(day,dt)-1)/10 when 0 then '上旬' when 1 then '中旬' else '下旬' end 
  
------------------------------------------------------------------------------------

另一种Convert 年月日分组方式

--按日
select convert(nvarchar(10),GETDATE(),120)
--按月
select convert(nvarchar(7),GETDATE(),120)
--按年
select convert(nvarchar(4),GETDATE(),120)

转载于:https://www.cnblogs.com/yangjinwang/p/6648408.html