HDU 2070 Fibbonacci Number

本文介绍了一个生成Fibonacci数列的C++程序,该程序能够计算从0到50范围内的任意指定项的Fibonacci数值。通过递推算法实现,确保了计算效率。

http://acm.hdu.edu.cn/showproblem.php?pid=2070

 

Problem Description
Your objective for this question is to develop a program which will generate a fibbonacci number. The fibbonacci function is defined as such:

f(0) = 0
f(1) = 1
f(n) = f(n-1) + f(n-2)

Your program should be able to handle values of n in the range 0 to 50.
 
Input
Each test case consists of one integer n in a single line where 0≤n≤50. The input is terminated by -1.
 
Output
Print out the answer in a single line for each test case.
 
Sample Input
3
4
5
-1
 
Sample Output
2
3
5
 
代码:
#include <bits/stdc++.h>

using namespace std;

const int maxn=1e5+10;

long long int f[maxn];

int main()
{
    int n;
    while(~scanf("%d",&n))
    {
        if(n==-1)
            break;
        for(int i=1; i<=50; i++)
        {
            if(i==1||i==2)
                f[i]=1;
            else
            {
                f[i]=f[i-1]+f[i-2];
            }
        }
        printf("%lld\n",f[n]);
    }
    return 0;
}

  

转载于:https://www.cnblogs.com/zlrrrr/p/9244003.html

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