分享一个linux系统中采用嵌套for循环比较两个数组内容，并输出相同值的shell脚本...

#!/bin/bash
array1=(1 3 5 6 7 9)
array2=(3 4 9)
echo array1=${array1[@]}
echo array2=${array2[@]}
for i in ${array1[@]};do
  for j in ${array2[@]};do
    if [ $i -eq $j ];then
      echo -e "\033[32m same number is $i \033[0m"
    fi
  done
done

　　

转载于:https://www.cnblogs.com/fusheng11711/p/10876150.html