upper_bound下确界

 1 //uppper_bound上确界找出首个大于某值的元素
 2 #include<algorithm>
 3 #include<iostream>
 4 
 5 using namespace std;
 6 
 7 int main()
 8 {
 9     int a[] = {23, 9, 7, 2, 3, 4};
10     int len = sizeof(a)/int (a);
11     int *x = upper_bound(a, a+len, 7);
12 
13     cout<<"不小于7的上确界元素为"<<*x<<endl;
14 
15     system("pause");
16 
17     return 0;
18 }

 

转载于:https://www.cnblogs.com/ruruozhenhao/p/8321091.html