统计某一句话里面 元音字母的个数

应用switch 语句，

 1 #include<stdio.h>
 2 int main(void)
 3 {    char ch;
 4     int a_ctl,e_ctl,i_ctl,o_ctl,u_ctl;
 5     a_ctl = e_ctl = i_ctl = o_ctl = u_ctl =0;
 6     printf("        Enter some text,and a # to quit\n"
 7         "        I will tell you the number of the vowel\n"    );
 8     while((ch=getchar()) != '#')
 9     {
10         switch(ch)
11         {
12             case 'A':
13             case 'a': a_ctl++;break;
14             case 'E':
15             case 'e': e_ctl++;break;
16             case 'I':
17             case 'i': i_ctl++;break;
18             case 'O':
19             case 'o': o_ctl++;break;
20             case 'U':
21             case 'u': u_ctl++;break;// 保留此处的break，为了方便以后添加其他选项 
22             default: break;
23         }
24         
25     }
26     printf("number of vowels: \n"
27         "a:%d    e:%d    i:%d    o:%d    u:%d\n",a_ctl,e_ctl,i_ctl,o_ctl,u_ctl);
28     return 0;
29 }

刚开始 把printf放在 while循环里面了，结果就悲剧了·····以后注意哈

转载于:https://www.cnblogs.com/kalo1111/p/3277879.html