select 获取option中其他的属性的值

<select name="tag_keys[]" id="category_type" required>
    <option value="" tag-id="">请选择</option>
</select>

$('#category_type').change(function () {
        var data = {
            type: $("#type").val(),
            parent_id: $(this).find("option:selected").attr("tag-id")
        };
    })

 

转载于:https://www.cnblogs.com/wjm956/p/10670716.html