(1)
public int findLast (int[] x, int y) { //Effects: If x==null throw NullPointerException // else return the index of the last element // in x that equals y. // If no such element exists, return -1 for (int i=x.length-1; i > 0; i--) { if (x[i] == y) { return i; } } return -1; } // test: x=[2, 3, 5]; y = 2 // Expected = 0
Identify the fault:for (int i = x.length -1; i > 0; i--)处应修改为for (int i = x.length -1; i >= 0; i--)
a test case that does not execute the fault:x=null y=2
a test case that executes the fault, but does not result in an error state:无
a test case that results in an error, but not a failure:x=[3, 2, 5] y = 2
(2)
public static int lastZero (int[] x) { //Effects: if x==null throw NullPointerException // else return the index of the LAST 0 in x. // Return -1 if 0 does not occur in x for (int i = 0; i < x.length; i++) { if (x[i] == 0) { return i; } } return -1; } // test: x=[0, 1, 0] // Expected = 2
Identify the fault:for (int i = 0; i < x.length; i++)处应修改为for (int i = x.length -1; i >= 0; i--)
a test case that does not execute the fault:x=null
a test case that executes the fault, but does not result in an error state:x=[0]
a test case that results in an error, but not a failure:x=[0, 1, 1]