A+B Coming 进制输入输出

最新推荐文章于 2020-10-23 12:57:01 发布

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最新推荐文章于 2020-10-23 12:57:01 发布

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原文链接：http://www.cnblogs.com/heqinghui/archive/2012/07/28/2613027.html

本文介绍了一个简单的编程问题——A+B问题，通过读取十六进制数并将其转换为十进制数相加来解决。使用C++实现，涉及基本的数据类型转换与输入输出操作。

A+B Coming

Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 3359    Accepted Submission(s): 2087

Problem Description

Many classmates said to me that A+B is must needs. If you can’t AC this problem, you would invite me for night meal. ^_^

Input
Input may contain multiple test cases. Each case contains A and B in one line. A, B are hexadecimal number. Input terminates by EOF.

Output

Output A+B in decimal number in one line.

Sample Input

1 9 A B a b

Sample Output

10 21 21

#include <iostream>
#include <stdio.h>
#include <string.h>
#include <algorithm>
using namespace std;
int main()
{
    int x,y;
    while(scanf("%x%x",&x,&y)!=EOF)//以十六进制输入，o为八进制，没有二进制输入法。
    {
        printf("%d\n",x+y);
    }
    return 0;
}

转载于:https://www.cnblogs.com/heqinghui/archive/2012/07/28/2613027.html