poj 3852 String LD

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原文链接：http://www.cnblogs.com/w0w0/archive/2011/11/23/2259880.html

String LD

Time Limit: 1000MS		Memory Limit: 65536K
Total Submissions: 488		Accepted: 262

Description

Stringld (left delete) is a function that gets a string and deletes its leftmost character (for instance Stringld(“acm”) returns “cm”).

You are given a list of distinct words, and at each step, we apply stringld on every word in the list. Write a program that determines the number of steps that can be applied until at least one of the conditions become true:

1) A word becomes empty string, or
2) a duplicate word is generated.

For example, having the list of words aab, abac, and caac, applying the function on the input for the first time results in ab, bac, and aac. For the second time, we get b, ac, and ac. Since in the second step, we have two ac strings, the condition 2 is true, and the output of your program should be 1. Note that we do not count the last step that has resulted in duplicate string. More examples are found in the sample input and output section.

Input

There are multiple test cases in the input. The first line of each test case is n (1 <= n <= 100), the number of words.
Each of the next n lines contains a string of at most 100 lower case characters.
The input terminates with a line containing 0.

Output

For each test case, write a single line containing the maximum number of stringld we can call.

Sample Input

4
aaba
aaca
baabcd
dcba
3
aaa
bbbb
ccccc
0

Sample Output

1
2

#include<iostream>
using namespace std;
int main()
{
char str[100][101];
int minlen;
int i,j,k;
int n;
int cut;
int flag;
while(1)
    {
        cin>>n;
if(n==0)
break;
        minlen=200;
for(i=0;i<n;i++)
        {
            cin>>str[i];
if(minlen>strlen(str[i]))
                minlen=strlen(str[i]);
        }
        cut=0;
        flag=0;
for(i=0;i<minlen;i++)
        {
if(flag==1)
break;
for(j=0;j<n;j++)
            {
if(flag==1)
break;
for(k=j+1;k<n;k++)
                {
if(flag==1)
break;
if(strcmp(str[j]+i,str[k]+i)==0)
                    {
                        flag=1;
break;
                    }
                }
            }
if(flag==0)
                cut++;
else 
break;
        }
        cout<<cut-1<<endl;
    }
return 0;
}

转载于:https://www.cnblogs.com/w0w0/archive/2011/11/23/2259880.html