[LeetCode] 58. Length of Last Word_Easy tag: String

转载于 2018-08-18 11:38:00 发布 · 46 阅读

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原文链接：http://www.cnblogs.com/Johnsonxiong/p/9496677.html

本文介绍了一种通过Python实现的方法，用于找出给定字符串中最后一个单词的长度。该方法首先去除字符串两端的空格，然后根据空格拆分字符串，并返回最后一个单词的长度。

Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string.

If the last word does not exist, return 0.

Note: A word is defined as a character sequence consists of non-space characters only.

Example:

Input: "Hello World"
Output: 5

就先利用s.strip()将前后的space去掉, 然后再用split(' ') 将最后的word的length得到并返回.

Code

class Solution:
    def lengthOfLastWord(self, s):
        s = s.strip()
        if not s: return 0
        return len(s.split(' ')[-1])

转载于:https://www.cnblogs.com/Johnsonxiong/p/9496677.html