1001. A+B Format (20)

A+B格式输出

最新推荐文章于 2021-02-19 15:05:15 发布

转载最新推荐文章于 2021-02-19 15:05:15 发布 · 45 阅读

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原文链接：http://www.cnblogs.com/brightz2017/p/6599871.html

本文介绍了一个简单的C++程序，用于解决两个整数相加的问题，并将结果以特定格式输出。程序考虑了各种边界情况，如负数和零的处理，确保输出结果符合标准格式要求。

1001. A+B Format (20)

Calculate a + b and output the sum in standard format -- that is, the digits must be separated into groups of three by commas (unless there are less than four digits).

Input

Each input file contains one test case. Each case contains a pair of integers a and b where -1000000 <= a, b <= 1000000. The numbers are separated by a space.

Output

For each test case, you should output the sum of a and b in one line. The sum must be written in the standard format.

Sample Input

-1000000 9

Sample Output

-999,991


注意:
　　1.0+0的情况
　　2.,199,9999的情况

#include <iostream>
#include <iomanip>
#include <math.h>
#include <stdio.h>
#include <string>
#include <algorithm>
#include <vector>
#include <map>
#include <stack>  
using namespace std;


int main()
{
    int a, b;
    cin >> a >> b;
    if (a + b < 0) cout << "-";
    int sum = abs(a + b);
    string s="";
    int cnt = 0;
    if (sum == 0)
        cout << 0;
    while (sum != 0)
    {
        if (cnt%3==0&&cnt!=0)
            s = "," + s;
        int temp = sum % 10;
        string t = to_string(temp);
        s = t + s;
        sum /= 10;
        cnt++;
    }
    
    
    cout << s;

    system("pause");
    return 0;
}

转载于:https://www.cnblogs.com/brightz2017/p/6599871.html