C++交换两个数组的前n个字节

 1 template<typename AnyType>
 2 void TestSwapNData(AnyType* a,AnyType* b,int n)
 3 {
 4     AnyType Temp;
 5     for (int i = 0; i < n; i++)
 6     {
 7         Temp = a[i];
 8         a[i] = b[i];
 9         b[i] = Temp;
10     }
11 }

代码中，typename 可以替换成关键字class,两个关键字的效果是一样的

示例使用

 1 int main()
 2 {
 3     char buf1[10] = {0};
 4     char buf2[10] = {0};
 5 
 6     memcpy(buf1,"123456789",sizeof("123456789") );
 7     memcpy(buf2,"abcdefghi",sizeof("abcdefghi") );
 8     std::cout<<buf1<<std::endl<<buf2<<std::endl;
 9 
10     TestSwapNData(buf1,buf2,5);
11     std::cout<<buf1<<std::endl<<buf2<<std::endl;
12 
13     return 0;
14 }

运行结果显示：

PS:前两行是交换之前的数据，后两行是交换之后的数据

 

转载于:https://www.cnblogs.com/LYF-LIUDAO/p/7809288.html