For Record

 

Meeting Minutes

Members: I`v`a`n` S`o, C`B L`o`w, C`Y C`h`a`n, B`e`e` A`y`e, C`h`e`n`M`i`n, X`i`a`o`F`a`n`g

(Add on comment from BI minutes in blue)

 

Operations (As attached):

1.       SMART will consider for the Mantis Scope per current productivity

[CB] - Will source 2 extra Mantis to cater Excel req (1 for P/IR and 1 for QA/QC)

2.       SAP for Plant 25, it is suggested to handle by Bee Aye. C`B` L`o`w` will discuss with David Harkin.

[CB] - All P25 transaction will be done in Pg. I will draft out a flow later. For interim until mid/end April, CY Chan will holding the responsibility

3.       Monthly forecast, need window to provide the quantity and period of time.

[CB] - Maggie/Halle will be providing these info

4.       Materials planning, deadline & frequency to provide.

[CB] - Maggie/Halle as single point of contact window between Smart and Excel. 

Joey will be the contact point on the materials support as well as the dram shipment arrangement. 

5.   All material to Excel will be send to HK (including PCB) to eliminate future custom issue to Excel.

       Bee Aye will coordinate with Maggie/Halle to ensure no shipment hold back due to Excel custom manual qty. (eg : CapA - manual btg 80K, plan ship 100K)

      Matl coordination, issuance of PO and those Joey is currently doing will not change. 

      We agreed that this month hic-up is mainly due to increase in demand and Excel could not react fast due to custom constrain.

6.   All ship plan, prod plan, NPI's will be coordinated between Bee Aye and Maggie/Halle.

7.   Chan to be free up from day to day task by early May for some other responsibility in China. Escalation or any help will still goes to Chan and follow by CB.

 

QA (As attached):

1.       PCB quality issue: SMART will consider for re-audit.

[CB] - Chan will work with Rajoo if that is needed.

 

Test (As attached):

1.       High Yield Loss for T3D400C38TS due to DRAM.

[CB] - We acknowledged that these are batch related and Excel has been doing a great job to contain it.

2.       Chenmin will provide the socket & motherboard requirement to CY Chan

3.    More role from Chen Min and Xiao Fang for RMA returns. (Direct deal if needed - Chan and Maggie to propose)

 

Others:

1.       NPI: Plan to start on mid-Apr for SODIMM, Registered DIMM & DDR II.

2.       SMART will provide the stencil & relevance information before NPI.

3.       C`B` L`o`w` will advice the stand for ROHS early April.

[CB] - BTU oven can cater for any memory module (only) RoHS build. At this point in time, there are no plan to upgrade it.

4.       HK Hub service: 1 head count + 300 sqf

-          2 layer rack

-          Job scope

-          Environment (CY Chan & Bee Aye will check out the temperature & humility next trip to Hk Hub)

[CB] - Ivan to provide quote and we will finalize the agreement with Janet.

 

[CB] - I hope this cover everything and this has been a great month for us to know Excel performance with 1 support crew.

Great JOB!!!

 

Best Regards,

 

C`B` L`o`w`

Sr. Manager

转载于:https://www.cnblogs.com/xcvm/archive/2006/03/29/362106.html

<think>好的,我现在需要解决用户的问题:如何使用Python列表推导式提取二维列表中每个子列表的第一个元素。首先,我得回忆一下列表推导式的基本结构。用户提到了二维列表,例如records,里面的每个record是一个子列表,要提取每个子列表的第一个元素。 首先,我应该考虑列表推导式的写法。通常,列表推导式的结构是[expression for item in iterable],所以对于二维列表来说,每个子项是子列表,那么需要遍历每个子列表,然后取第一个元素。比如,假设有一个二维列表records = [[1,2,3], [4,5,6], [7,8,9]],要取出每个子列表的第一个元素,结果应该是[1,4,7]。 接下来,我需要确认如何访问每个子列表的第一个元素。在Python中,可以通过索引0来获取第一个元素,所以对于每个子列表record,表达式应该是record[0]。因此,列表推导式应该是这样的:[record[0] for record in records]。 然后,我需要考虑用户可能的疑问,比如如果子列表为空怎么办。这时候访问record[0]会引发IndexError错误。但用户的问题可能假设所有子列表都有至少一个元素,所以可能不需要处理这种情况。不过,如果有需要的话,可能需要添加条件判断,比如[record[0] for record in records if record],这样可以跳过空列表。但用户的问题中没有提到这种情况,所以可能暂时不需要考虑。 另外,根据用户提供的引用内容,他们之前提到的列表推导式例子中有类似的结构,例如将二维列表转化为一维列表的例子。用户引用中的例子是使用嵌套的列表推导式,但这里的情况更简单,只需要提取每个子列表的第一个元素,不需要嵌套。 可能还需要举例说明,比如用户提到的matrix的例子,如果使用同样的结构,提取第一个元素的话,应该是[row[0] for row in matrix],这样就能得到每个子列表的第一个元素组成的列表。用户的问题中的records相当于这里的matrix,所以同样的方法适用。 然后,我需要验证这个方法的正确性。比如,使用用户给的示例matrix = [[1,2,3],[4,5,6],[7,8,9]],用这个列表推导式会得到[1,4,7],这和预期一致。 最后,我应该总结步骤:首先遍历二维列表中的每个子列表,然后对每个子列表取索引0的元素,组合成新的列表。这样用户就能清晰地理解如何实现。</think>要使用Python列表推导式提取二维列表$records$中每个子列表的第一个元素,可以按照以下步骤操作: 1. **基本语法**:列表推导式的核心结构是`[表达式 for 元素 in 可迭代对象]`。这里需要遍历每个子列表,并取第一个元素。 2. **索引访问**:通过索引`[0]`获取子列表的第一个元素,例如`record[0]`表示子列表的第一个元素。 3. **完整推导式**:组合上述逻辑,推导式为`[record[0] for record in records]`。 **示例代码**: ```python records = [[10, "A"], [20, "B"], [30, "C"]] first_elements = [record[0] for record in records] print(first_elements) # 输出:[10, 20, 30] ``` **注意事项**: - 若子列表可能为空,需添加条件过滤,如`[record[0] for record in records if record]`[^2]。 - 推导式会生成新列表,原始数据不会被修改[^1]。
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