Leetcode 83: Remove Duplicates from Sorted List

Given a sorted linked list, delete all duplicates such that each element appear only once.

For example,
Given 1->1->2, return 1->2.
Given 1->1->2->3->3, return 1->2->3.

 

 1 /**
 2  * Definition for singly-linked list.
 3  * public class ListNode {
 4  *     public int val;
 5  *     public ListNode next;
 6  *     public ListNode(int x) { val = x; }
 7  * }
 8  */
 9 public class Solution {
10     public ListNode DeleteDuplicates(ListNode head) {
11         if (head == null) return null;
12         
13         ListNode prior = head, cur = head.next;
14         
15         while (cur != null)
16         {
17             if (cur.val != prior.val)
18             {
19                 cur = cur.next;
20                 prior = prior.next;
21             }
22             else
23             {
24                 cur = cur.next;
25                 prior.next = cur;
26             }
27         }
28         
29         return head;
30     }
31 }

 

转载于:https://www.cnblogs.com/liangmou/p/7824676.html

评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值