zoj 2201 No Brainer

最新推荐文章于 2025-08-13 16:29:18 发布

转载最新推荐文章于 2025-08-13 16:29:18 发布 · 85 阅读

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原文链接：http://www.cnblogs.com/qinduanyinghua/p/6531213.html

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#运维

这是一个简单的编程问题，通过比较僵尸吃的脑数量与生存所需的脑数量来判断僵尸是否能存活。输入包括多个数据集，每个数据集包含两个整数：吃掉的脑数和生存所需的脑数。如果吃的脑数大于等于所需的脑数，则输出MMMBRAINS；否则输出NOBRAINS。

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No Brainer

Time Limit: 2 Seconds Memory Limit: 65536 KB

Zombies love to eat brains. Yum.

Input

The first line contains a single integer n indicating the number of data sets.

The following n lines each represent a data set. Each data set will be formatted according to the following description:

A single data set consists of a line "X Y", where X is the number of brains the zombie eats and Y is the number of brains the zombie requires to stay alive.

Output

For each data set, there will be exactly one line of output. This line will be "MMM BRAINS" if the number of brains the zombie eats is greater than or equal to the number of brains the zombie requires to stay alive. Otherwise, the line will be "NO BRAINS".

Sample Input

3
4 5
3 3
4 3

Sample Output

NO BRAINS
MMM BRAINS
MMM BRAINS

。。。好水的题

 1 #include <iostream>
 2 #include <cstdio>
 3 using namespace std;
 4 int main(){
 5     int x, y;
 6     int n;
 7     cin >> n;
 8     while(n--){
 9         cin >> x >> y;
10         if(x >= y)
11             cout << "MMM BRAINS" << endl;
12         else
13             cout << "NO BRAINS" << endl;
14     }
15     return 0;
16 }