[leetcode]158. Read N Characters Given Read4 II - Call multiple times 用Read4读取N个字符2 - 调用多次...

转载于 2018-10-18 06:25:00 发布 · 113 阅读

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原文链接：http://www.cnblogs.com/liuliu5151/p/9808266.html

本文介绍了一种利用read4 API实现read函数的方法，该函数可以从文件中读取指定数量的字符。通过实例展示了如何在不同情况下使用此函数，如读取少于或等于请求字符数的情况。

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The API: int read4(char *buf) reads 4 characters at a time from a file.

The return value is the actual number of characters read. For example, it returns 3 if there is only 3 characters left in the file.

By using the read4 API, implement the function int read(char *buf, int n) that reads n characters from the file.

Note:
The read function may be called multiple times.

Example 1:

Given buf = "abc"
read("abc", 1) // returns "a"
read("abc", 2); // returns "bc"
read("abc", 1); // returns ""

Example 2:

Given buf = "abc"
read("abc", 4) // returns "abc"
read("abc", 1); // returns ""

转载于:https://www.cnblogs.com/liuliu5151/p/9808266.html