When $a \ne 0$, there are two solutions to \(ax^2 + bx + c = 0\) and they are
$$x = {-b \pm \sqrt{b^2-4ac} \over 2a}.$$
$$x = {-b \pm \sqrt{b^2-4ac} \over 2a}.$$
转载于:https://www.cnblogs.com/wf-strongteam/p/9040376.html
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本文提供了当$a \ne 0$时一元二次方程$ax^2 + bx + c = 0$的两个解的公式，即$x = {-b \pm \sqrt{b^2-4ac}
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