uva 541 - Error Correction

最新推荐文章于 2025-09-05 14:41:09 发布

转载最新推荐文章于 2025-09-05 14:41:09 发布 · 112 阅读

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原文链接：http://www.cnblogs.com/flyfy1/archive/2012/01/01/2309508.html

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#开发工具

本文详细介绍了如何通过计算矩阵每一行和每一列的数字之和来判断矩阵是否被篡改的问题。重点在于通过检查奇偶数之和来确定矩阵的完整性。对于遇到的特定问题，作者提供了AC代码作为解决方案，确保了对初学者的指导性和实践性。

Problem: http://uva.onlinejudge.org/external/5/541.html

Basic Idea: calculate the sum of each row and each column respectively. If found any more than two row/column has an odd sum, or one row has odd sum, but all column have even sum, then it's corrupted; if one row & one column has old sum, then the point on that row/column is to be changed. Otherwise it would be correct

ACed Code:

转载于:https://www.cnblogs.com/flyfy1/archive/2012/01/01/2309508.html