java double算法，保留固定位小数

public static void main(String[] args) {

double a = 26765;
int b = 45676;
double c = a/b;
double d = a/b/1.000;
double e = a/1000.00;
String result = String.format("%.3f",c);//  %-小数点前任意位数；3-小数点后三位； f-浮点型

System.out.println("c="+result);
System.out.println("d="+d);
System.out.println("e="+e);

}

运算结果：

c=0.586
d=0.5859751291706804
e=26.765

转载于:https://www.cnblogs.com/qqzhulu/p/10246966.html