JavaScript找出唯一不同的数字-优快云博客

本文介绍了通过数组找出唯一不同数值的两种实现方案。一种是使用indexOf和lastIndexOf方法定位该数值；另一种则是先对数组进行排序，再找出位于特定位置的不同数值。这两种方法都适用于有效且长度为奇数的数组。

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Description:

You are given an odd-length array of integers, in which all of them are the same, except for one single number.

Implement the method stray which accepts such array, and returns that single different number.

The input array will always be valid!(odd-length >= 3)

Examples:

[1, 1, 2] => 2

[17, 17, 3, 17, 17, 17, 17] => 3

my answer：用检索法

IndexOf()返回某个指定的字符串值在字符串中首次出现的位置
lastIndexOf返回某个指定的字符串值在字符串中最后出现的位置

function stray(numbers){
  for (var i in numbers){
     if (numbers.indexOf(numbers[i]) === numbers.lastIndexOf(numbers[i])){return numbers[i];}
  }
}

console.log(stray([1, 1, 2])); // 2
console.log(stray([17, 17, 3, 17, 17, 17, 17]));  // 3

other answer：

用sort()排序

function stray(numbers) {
  var a = numbers.sort();
  
  if(a[0] != a[1]) {
    return a[0];
  } 
  return a[a.length-1];
}

console.log(stray([1, 1, 2])); // 2
console.log(stray([17, 17, 3, 17, 17, 17, 17]));  // 3

转载于:https://www.cnblogs.com/kid2333/p/7447666.html