[RxJS] Sharing Streams with Share-优快云博客

本文介绍如何利用RxJS操作符优化游戏计分系统的实现过程，通过使用share操作符来避免多次订阅同一数据流导致的问题，并展示了如何在计分逻辑中加入清理输入框的功能。

A stream will run with each new subscription added to it. This lesson shows the benefits of using share so that the same stream can be shared across multiple subscriptions.

const timer$ = starters$
    .switchMap(intervalActions)
    .startWith(data)
    .scan((acc, curr)=> curr(acc))


timer$
    .do((x)=> console.log(x))
    .takeWhile((data)=> data.count <= 3)
    .withLatestFrom(
        input$.do((x)=> console.log(x)),
        (timer, input)=> ({count: timer.count, text: input})
    )
    .filter((data)=> data.count === parseInt(data.text))
    .reduce((acc, curr)=> acc + 1, 0)
    .repeat()
    .subscribe(
        (x)=> document.querySelector('#score').innerHTML = `
            ${x}
        `,
        err=> console.log(err),
        ()=> console.log('complete')
    );

Current code has a problem every time we type in the input, we need to click delete keyborad to delete the input. This is not conveninet.

So what we want is every time when the code check whether the value match, then we clean the input:

const runningGame$ = timer$
    .do((x)=> console.log(x))
    .takeWhile((data)=> data.count <= 3)
    .withLatestFrom(
        input$.do((x)=> console.log(x)),
        (timer, input)=> ({count: timer.count, text: input})
    );

runningGame$
  .subscribe( (x) => input.value = "");

 runningGame$
    .filter((data)=> data.count === parseInt(data.text))
    .reduce((acc, curr)=> acc + 1, 0)
    .repeat()
    .subscribe(
        (x)=> document.querySelector('#score').innerHTML = `
            ${x}
        `,
        err=> console.log(err),
        ()=> console.log('complete')
    );

So we split the code and add another subscribe to clean the input, but now the problem is everytime it console log twice. This is because we have two subscribe on the runningGame$.

TO solve this problem, we need to share() the stream:

const runnintGame$ = timer$
    .do((x)=> console.log(x))
    .takeWhile((data)=> data.count <= 3)
    .withLatestFrom(
        input$.do((x)=> console.log(x)),
        (timer, input)=> ({count: timer.count, text: input})
    )
.share();

Now it only log out once, but it doesn't clean the input when we click start again. THis is because we only repeat() this part of code:

 runningGame$
    .filter((data)=> data.count === parseInt(data.text))
    .reduce((acc, curr)=> acc + 1, 0)
    .repeat()

What we need to do is also make runningGame$ (clean the input) stream repeat itself:

// To clean the input
runningGame$
  .repeat()
  .subscribe( (x) => input.value = "");

----------------------------

Code:

const timer$ = starters$
    .switchMap(intervalActions)
    .startWith(data)
    .scan((acc, curr)=> curr(acc))


const runningGame$ = timer$
    .do((x)=> console.log(x))
    .takeWhile((data)=> data.count <= 3)
    .withLatestFrom(
        input$.do((x)=> console.log(x)),
        (timer, input)=> ({count: timer.count, text: input})
    )
.share();

// To clean the input
runningGame$
  .repeat()
  .subscribe( (x) => input.value = "");

 runningGame$
    .filter((data)=> data.count === parseInt(data.text))
    .reduce((acc, curr)=> acc + 1, 0)
    .repeat()
    .subscribe(
        (x)=> document.querySelector('#score').innerHTML = `
            ${x}
        `,
        err=> console.log(err),
        ()=> console.log('complete')
    );