keepalived 检测脑裂切换脚本

最新推荐文章于 2021-10-24 22:52:23 发布

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最新推荐文章于 2021-10-24 22:52:23 发布

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CC 4.0 BY-SA版权

文章标签： python 数据库

原文链接：http://www.cnblogs.com/wangmo/p/9078209.html

本文介绍了一个使用Shell脚本来监控多个HTTP服务及MySQL数据库运行状态的例子。该脚本通过发送HTTP请求检查指定端口上的服务是否返回200 OK状态，并定期尝试连接数据库以确认其可用性。当检测到服务失败时，脚本会尝试重启服务并记录日志，如果连续多次重启失败，则通过邮件通知管理员并停止Keepalived服务。

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#!/bin/bash

count=0
run1=`curl -I  192.168.30.12:8000 | grep "200 OK"  | wc -l`
run2=`curl -I  192.168.30.12:8020 | grep "200 OK"  | wc -l`
run3=`curl -I  192.168.30.12:8080 | grep "200 OK"  | wc -l`
run=$[$run1 + $run2 + $run3]


for (( k=0; k<10; k++ )) ; do
    /usr/bin/mysql -uroot -p'123456!' -h'192.168.30.21' -e "show databases;" > /dev/null
    if [ $? != 0 ];then
        echo "mysql faild !" >> /etc/keepalived/keepalived.log
        break
    fi
    if [ $run -ne 3 ] ; then
        sleep 2
        /etc/init.d/httpd start
        run1=`curl -I  192.168.30.12:8000 | grep "200 OK"  | wc -l`
        run2=`curl -I  192.168.30.12:8020 | grep "200 OK"  | wc -l`
        run3=`curl -I  192.168.30.12:8080 | grep "200 OK"  | wc -l`
        run=$[$run1 + $run2 + $run3]
        count=$(($count+1))
        echo "httpd start $count  faild !" >> /etc/keepalived/keepalived.log
    else
        #echo "httpd start $count  ok !" >> /etc/keepalived/keepalived.log
        break
    fi
    if [ "$count" == "9" ]; then
        /etc/init.d/keepalived stop
        echo “192.168.30.12 keepalived changed” | mail -s "keepalived changd" team_cloud_service@syberos.com
        echo "keepalived change !" >> /etc/keepalived/keepalived.log
        break
    fi
done