Bash if判断

最新推荐文章于 2025-04-20 09:07:35 发布

weixin_30716141

最新推荐文章于 2025-04-20 09:07:35 发布

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原文链接：http://www.cnblogs.com/schangech/p/5630317.html

版权

Bash 中，判断某个变量是否在指定字符串中。

以下为用于根据IP判断机房

if ([[ $ip =~ "*.*.*" ]] || [[ $ip =~ "*.*.*" ]]); then
    idc="jyw"
elif([[ $ip =~ "*.*.*" ]] || [[ $ip =~ "*.*.*" ]] || [[ $ip =~ "*.*.*" ]] || [[ $ip =~ "*.*.*" ]]); then
    idc="dzc"
elif([[ $ip =~ "*.*" ]] || [[ $ip =~ "123.103" ]] || [[ $ip =~ "202.108" ]] || [[ $ip =~ "123.*.*" ]]); then
    idc="syq"
elif([[ $ip =~ "124.*" ]] || [[ $ip =~ "*.*" ]] || [[ $ip =~ "124.2*" ]] ); then
    idc="sjhl"
elif([[ $ip =~ "180.163" ]] || [[ $ip =~ "180.153" ]]); then
    idc="nh"
elif([[ $ip =~ "42.62.*" ]] || [[ $ip =~ "42.*" ]]); then
    idc="jyw"
else
    idc="jyw"
fi

转载于:https://www.cnblogs.com/schangech/p/5630317.html