2013暑假集训B组训练赛第二场 - A Bus Game-优快云博客

本文介绍了一个名为BusGame的游戏，分析了游戏规则及胜负条件。游戏中两位玩家轮流从一堆硬币中取出价值220日元的硬币组合，具体策略包括优先取100日元硬币或10日元硬币等。

A - Bus Game

Time Limit:2000MS Memory Limit:262144KB 64bit IO Format:%I64d & %I64u

Description

After Fox Ciel won an onsite round of a programming contest, she took a bus to return to her castle. The fee of the bus was 220 yen. She met Rabbit Hanako in the bus. They decided to play the following game because they got bored in the bus.

Initially, there is a pile that contains x 100-yen coins and y 10-yen coins.
They take turns alternatively. Ciel takes the first turn.
In each turn, they must take exactly 220 yen from the pile. In Ciel's turn, if there are multiple ways to take 220 yen, she will choose the way that contains the maximal number of 100-yen coins. In Hanako's turn, if there are multiple ways to take 220 yen, she will choose the way that contains the maximal number of 10-yen coins.
If Ciel or Hanako can't take exactly 220 yen from the pile, she loses.

Determine the winner of the game.

Input

The first line contains two integers x (0 ≤ x ≤ 10⁶) and y (0 ≤ y ≤ 10⁶), separated by a single space.

Output

If Ciel wins, print "Ciel". Otherwise, print "Hanako".

Sample Input

Input

2 2

Output

Ciel

Input

3 22

Output

Hanako



很简单的循环，判断

#include <cstdio>

int x, y;

int main()
{
    while(~scanf("%d%d",&x,&y))
    {
        while(x >= 0&& y>=0)
        {
            if(x>=2 && y >= 2)
            {
                x -= 2;
                y -= 2;
            }
            else if(x==1 && y >= 12)
            {
                x -= 1;
                y -= 12;
            }
            else if(x== 0 && y>=22)
            {
                y -= 22;
            }
            else
            {
                puts("Ciel");
                break;

            }


            if(y>=22)
            {
                y -= 22;
            }
            else if(y>=12 && x >=1)
            {
                x -= 1;
                y -= 12;
            }
            else if(x>= 2 && y >=2)
            {
                x -= 2;
                y -= 2;
            }
            else
            {
                puts("Hanako");
                break;

            }
        }
    }

}