[Algorithm -- Dynamic programming] How Many Ways to Decode This Message?-优快云博客

本文探讨了解码数字字符串为字母的多种方式，通过动态规划和记忆化递归的方法，解决了给定数字字符串的不同解码方式计数问题。以1246为例，详细解析了算法实现过程。

For example we have

'a' -> 1

'b' -> 2

'z' -> 26

By given "12", we can decode the string to give result "ab" or 'L', 2 ways to decode, your function should return 2 as an answer.

Now asking by given "1246", what should be the return number;

The thinking process is somehow like this:

by given "1" -> we got 'a'

by given "" -> we got ""

by given "12345" -> 'a' + decode('2345') or 'L' + decode('345'), therefore number of ways to decode "12345"is the same of decode(2345)+decode(345).

Somehow we can see that this is a recursion task, therefore we can use Dynamice Programming + memo way to solve the problem.

const data = "1246";

function num_ways(data) {
  // k : count from last to beginning
  function helper(data, k, memo) {
    if (k === 0) {
      // if k equals 0, mean only one single digital number left
      // means there must be one char
      return 1;
    }

    if (data === "") {
      // if data equals empty, then return 1
      return 1;
    }

    if (memo[k] != null) {
      return memo[k];
    }

    const start = data.length - k;
    if (data[start] === "0") {
      // if sth start as 0, then no char
      return 0;
    }

    let result = helper(data, k - 1, memo);

    if (k >= 2 && parseInt(data.slice(start, start + 2), 10) <= 26) {
      result += helper(data, k - 2, memo);
    }

    memo[k] = result;

    return result;
  }

  let memo = [];
  return helper(data, data.length, memo);
}

const res = num_ways(data);
console.log(res); // 3