1100. Mars Numbers (20)

本文介绍了一个程序设计问题,即实现地球十进制与火星十三进制计数系统的相互转换。火星计数系统使用独特的数字名称,如将地球上的1到12分别命名为jan至dec,并为更高位数定义了新的名称。程序需要读取输入的数字,并将其从一种计数系统转换为另一种。

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People on Mars count their numbers with base 13:

  • Zero on Earth is called "tret" on Mars.
  • The numbers 1 to 12 on Earch is called "jan, feb, mar, apr, may, jun, jly, aug, sep, oct, nov, dec" on Mars, respectively.
  • For the next higher digit, Mars people name the 12 numbers as "tam, hel, maa, huh, tou, kes, hei, elo, syy, lok, mer, jou", respectively.

For examples, the number 29 on Earth is called "hel mar" on Mars; and "elo nov" on Mars corresponds to 115 on Earth. In order to help communication between people from these two planets, you are supposed to write a program for mutual translation between Earth and Mars number systems.

Input Specification:

Each input file contains one test case. For each case, the first line contains a positive integer N (< 100). Then N lines follow, each contains a number in [0, 169), given either in the form of an Earth number, or that of Mars.

Output Specification:

For each number, print in a line the corresponding number in the other language.

Sample Input:
4
29
5
elo nov
tam
Sample Output:
hel mar
may
115
13

 


   
  1. #include <iostream>
  2. #include <stdio.h>
  3. #include <string>
  4. #include <memory>
  5. #include <string.h>
  6. #pragma warning(disable:4996)
  7. using namespace std;
  8. string gewei[12] = { "jan", "feb", "mar", "apr", "may", "jun", "jly", "aug", "sep", "oct", "nov", "dec" };
  9. string shiwei[12] = { "tam", "hel", "maa", "huh", "tou", "kes", "hei","elo", "syy", "lok", "mer", "jou" };
  10. int main(void) {
  11. int n;
  12. // cin >> n;
  13. scanf("%d\n", &n);
  14. string s="";
  15. for (int i = 0; i < n; i++) {
  16. s = "";
  17. //cin >> s;
  18. char a[10];
  19. memset(a, 0, sizeof(a));
  20. int k = 0;
  21. while (1) {
  22. scanf("%c", &a[k]);
  23. if (a[k] != '\n') {
  24. s += a[k];
  25. k++;
  26. }
  27. else {
  28. break;
  29. }
  30. }
  31. if (s[0] >= '0'&&s[0] <= '9') {
  32. int num=0;
  33. for (int i = 0; i <= s.length() - 1; i++) {
  34. num = num * 10;
  35. num += s[i] - '0';
  36. }
  37. if (num < 13&&num>0) {
  38. cout << gewei[num-1] << endl;
  39. }
  40. else if (num != 0) {
  41. if (num % 13 != 0)
  42. cout << shiwei[num / 13 - 1] << " " << gewei[num % 13 - 1] << endl;
  43. else
  44. cout << shiwei[num / 13 - 1] << endl;
  45. }
  46. else
  47. cout << "tret" << endl;
  48. }
  49. else {
  50. int marsnum = 0;
  51. if (s.length() == 3) {
  52. for (int j = 0; j < 12; j++) {
  53. if (s == gewei[j]) {
  54. marsnum = j+1;
  55. break;
  56. }
  57. }
  58. for (int j = 0; j < 12; j++) {
  59. if (s == shiwei[j]) {
  60. marsnum = j*13+13;
  61. break;
  62. }
  63. }
  64. }
  65. else {
  66. string s1="", s2="";
  67. for (int j = 0; j < 3; j++)
  68. s1 += s[j];
  69. for (int j = 4; j < 7; j++)
  70. s2 += s[j];
  71. int gaowei = 0, diwei = 0;
  72. for (int j = 0; j < 12; j++) {
  73. if (s2 == gewei[j]) {
  74. diwei = j + 1;
  75. break;
  76. }
  77. }
  78. for (int j = 0; j < 12; j++) {
  79. if (s1 == shiwei[j]) {
  80. gaowei = j + 1;
  81. break;
  82. }
  83. }
  84. marsnum = gaowei * 13 + diwei;
  85. }
  86. cout << marsnum << endl;
  87. }
  88. }
  89. /*while (true)
  90. {
  91. }*/
  92. return 0;
  93. }


   
  1. #include <string>
  2. #include <iostream>
  3. #include <stdio.h>
  4. #pragma warning(disable:4996)
  5. using namespace std;
  6. string diwei[13] = {"", "jan", "feb", "mar", "apr", "may", "jun", "jly", "aug", "sep", "oct", "nov", "dec" };
  7. string gaowei[13] = { "", "tam", "hel", "maa", "huh", "tou", "kes", "hei", "elo", "syy", "lok","mer", "jou" };
  8. int main(void) {
  9. int n;
  10. //cin >> n;
  11. scanf("%d", &n);
  12. char c;
  13. for (int i = 0; i < n; i++) {
  14. string s="";
  15. while (true)
  16. {
  17. scanf("%c", &c);
  18. if (c == '\n'&&s.length()>0)
  19. break;
  20. else if(c!='\n')
  21. s += c;
  22. }
  23. if (s[0] >= '0'&&s[0] <= '9') {
  24. int num=0;
  25. for (int i = 0; i < s.length(); i++)
  26. num = num * 10 + s[i] - '0';
  27. if (num == 0)
  28. cout << "tret" << endl;
  29. else if (num < 13)
  30. cout << diwei[num] << endl;
  31. else if (num % 13 == 0)
  32. cout << gaowei[num / 13] << endl;
  33. else
  34. cout << gaowei[num / 13] << " " << diwei[num % 13] << endl;
  35. }
  36. else {
  37. if (s.length() == 3) {
  38. for (int i = 0; i < 13; i++) {
  39. if (s == diwei[i])
  40. cout << i << endl;
  41. if (s == gaowei[i])
  42. cout << 13 * i << endl;
  43. }
  44. }
  45. else if (s.length() == 4) {
  46. cout << "0" << endl;
  47. }
  48. else {
  49. string s1, s2;
  50. for (int i = 0; i < 3; i++) {
  51. s1 += s[i];
  52. s2 += s[i + 4];
  53. }
  54. int mnum=0;
  55. for (int i = 0; i < 13; i++) {
  56. if (diwei[i] == s2)
  57. mnum += i;
  58. if (gaowei[i] == s1)
  59. mnum += 13 * i;
  60. }
  61. cout << mnum << endl;
  62. }
  63. }
  64. }
  65. }





转载于:https://www.cnblogs.com/zzandliz/p/5023351.html

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