459. Repeated Substring Pattern

本文介绍了一种算法,用于检查一个非空字符串是否可以通过多次重复其子串构成。通过实例展示,如输入abab,输出为真,解释为ab两次重复;而输入aba则为假。文章提供了Python实现代码,利用循环和条件判断来验证字符串是否由重复子串组成。

Given a non-empty string check if it can be constructed by taking a substring of it and appending multiple copies of the substring together. You may assume the given string consists of lowercase English letters only and its length will not exceed 10000.

Example 1:

Input: "abab"
Output: True
Explanation: It's the substring "ab" twice.

Example 2:

Input: "aba"
Output: False

Example 3:

Input: "abcabcabcabc"
Output: True
Explanation: It's the substring "abc" four times. (And the substring "abcabc" twice.)

class Solution:
    def repeatedSubstringPattern(self, s):
        """
        :type s: str
        :rtype: bool
        """
        def judge(i):
            pos = i + i
            while pos<=len(s):
                if s[pos-i:pos]!=s[:i]:
                    return False
                pos += i
            return True
        for i in range(1,len(s)):
            if len(s)%i!=0:
                continue
            if judge(i):
                return True
        return False

转载于:https://www.cnblogs.com/bernieloveslife/p/9775259.html

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