48. Anagrams

Given an array of strings, return all groups of strings that are anagrams.

Note: All inputs will be in lower-case.

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public class Solution {
    public ArrayList<String> anagrams(String[] strs) {

        ArrayList<String> rst = new ArrayList<String>();
        HashMap<String, ArrayList<String>> map = new HashMap<String, ArrayList<String>>();
        
        for (String s : strs) {
            char[] c = s.toCharArray();
            java.util.Arrays.sort(c);
            String newStr = new String(c);

            if (map.containsKey(newStr)) {
                map.get(newStr).add(s);
                
            } else {
                ArrayList<String> analist = new ArrayList<String>();
                analist.add(s);
                map.put(newStr, analist);
            }
        }

        for (String s2 : map.keySet()) {
            if (map.get(s2).size() > 1) {
                rst.addAll(map.get(s2));
            }
        }
        return rst;
    }
}

 

 

转载于:https://www.cnblogs.com/ycled/p/3306695.html